2x^2-25x-27=0

Solution for 2x^2-25x-27=0 equation:

2x^2-25x-27=0

a = 2; b = -25; c = -27;
Δ = b2-4ac
Δ = -252-4·2·(-27)
Δ = 841
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{841}=29$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-25)-29}{2*2}=\frac{-4}{4}
=-1
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-25)+29}{2*2}=\frac{54}{4}
=13+1/2
$